a)
Grundformel
s = v·t
t = s/v = (200 m)/(5 m/s + 4 m/s) = 22.22 s bei Talfahrt
t = s/v = (200 m)/(5 m/s - 4 m/s) = 200 s bei Bergfahrt
b)
t = s/v = (400 m)/(5 m/s) = 80 s bei ruhendem Wasser
c)
t = s/v = (200 m)/(5 m/s) = 40 s
s = v·t = (4 m/s)·(40 s) = 160 m wird es abgetrieben
d)
SIN(α) = v1 / v2 = (4 m/s) / (5 m/s) = 0.8
α = ASIN(0.8) = 53.13°
v = √(v2^2 - v1^2) = √((5·m/s)^2 - (4·m/s)^2) = 3 m/s
t = s/v = (200 m)/(3 m/s) = 66.67 s